[最も欲しかった] ab bc ca formula 257134
How To Prove Math A 2 B 2 C 2 Ab Ca Math Is Non Negative For All Values Of Math A B Math And Math C Quora Multiply both sides with 2, we get 2 ( a2 b2 c2 – ab – bc – ca) = 0 ⇒ 2a2 2b2 2c2 – 2ab – 2bc – 2ca = 0 ⇒ (a2 – 2ab b2) (b2 – 2bc c2) (c2 – 2ca a2) = 0 ⇒ (a –b)2 (b – c)2 (c – a)2 = 0 Since the sum of square is zero then each term should be zero ⇒ (a –b)2 = 0, (b – c)2 = 0, (c – a)2 = 0 AB A'C BC I know it simplifies to A'C BC And I understand why, but I cannot figure out how to perform the simplification through the expression using the boolean algebra identities I was wondering if someone could show me the steps needed to do this Thank you in advance booleanalgebra Share Ab bc ca formula